Thread: Printing problem when I use NULL

I initialize array with characters a2[3][4] from a1 array and I want to insert a NULL ‘\0’ to the items a2[i][4] in the array and then when I Print the array I don’t get all characters printed and I don’t know why, and when I don’t store ‘\0’ it prints ok.

Code:

#include <stdio.h>

int main()
{


    int a1[3][3];
    char a2[3][4];
    char a3[10]= {'*','#','@','%','&','!','^','>','<',':'};

    int i,j;

     a1[0][0]=6;        /* storing values in the array a1 */
     a1[0][1]=3;
     a1[0][2]=0;

     a1[1][0]=4;
     a1[1][1]=9;
     a1[1][2]=2;

     a1[2][0]=2;
     a1[2][1]=6;
     a1[2][2]=7;


            
         for (i=0;i<=2;i++)
         {
            for (j=0;j<=2;j++)
            {
                a2[i][j]= a3[a1[i][j]]; /* storing characters in the array a2 */


                if (j = 2)
                    a2[i][j+1]='\0';  /* storing null in a2[i][3] */
                                      /* ****** the problem in the above line */
            }
          }
         printf("\n");

         for (i=0;i<=2;i++)
         {
            for (j=0;j<=3;j++)
            {
                 printf("%c",a2[i][j]); /* printing character from array a2 */
                                   }
            }


	return(0);
}

You are right it was off, I turned it on,
and the problem is solved .. many thanks.