Help with problem

[renniegq]

I'm having problem with the while loop and switch statements. I can run case 1 all the way through, but when I input case 2 the program ends, what am I doing wrong? Please help.

 
#include <stdio.h>

void main(void)


{	int paycode, hours;
	float hourly_rate, weekly_pay, weekly_salary, weekly_sales;

	
	printf("Enter employee paycode (-1 to end): ");
	scanf("%i", &paycode);	
	
	switch (paycode)
	while (paycode = -1)
	{
		case 1:		
			printf("	Enter the weekly salary: ");
			scanf("%i", &weekly_salary);
			weekly_salary = 400;
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_salary);	
			break;
		case 2:
			printf("	Enter the employee's hourly rate: ");
			scanf("%f", &hourly_rate);
			printf("	Enter the hours worked: ");
			scanf("%i", &hours);
			if(hours <= 40)
			{
				weekly_pay = hourly_rate * hours;
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);			
			}
			else if(hours > 40)
			{
				weekly_pay = (hourly_rate * 40) + ((1.5 * 12.50) * 5);
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);
			}
			break;
		case 3:
			printf("	Enter the gross weekly sales: ");
			scanf("%i", &weekly_sales);
			weekly_sales = 250 + (1000 * .057);
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_sales);
			break;
	}
		printf("Enter employee paycode (-1 to end): ");
		scanf("%i", &paycode);	
			
		
		

}

[Sebastiani]

>> I'm having problem with the while loop

I'd say!


>> while (paycode = -1)

1) While loops don't get inserted in switch'es like that. You can put a while loop *after* a 'case' or 'default' label, but not otherwise.

2) You are assigning paycode the value -1 here. Don't confuse '=' with '=='.

Try something like:

int main(void) // main() *always* returns an 'int'.
{
 int paycode = 0; 
 
 // code 

  while(paycode != -1)
 {
  printf("Enter employee paycode (-1 to end): ");
  scanf("%i", &paycode);	
  	
      switch (paycode)
     {
        // code    
     }
 }

 // code

 return 0;  // there's that 'int' :)
}

[renniegq]

I kind of figured I had a problem. I'll try your suggestion. Thank you.

[renniegq]

I am still stuck, is that C++ code? I am programming in C, I'm not understanding what needs to b done, any other help please?

[Sebastiani]

Be specific. What is the exact problem you are having at this point? Feel free to post code.

>> I am programming in C

Yes, that's C.

[renniegq]

when I run the program, I'm prompted for employee paycode and I type in 1 and then I enter the weekly salary of $400, it calculates the weekly pay just fine, it then prompts me to enter paycode I type in 2 and the program ends with press enter to continue. I'm using Visual Studio C++ to build C programs. Is there something wrong with my switch or if-else if statements also? I do appreciate your help.

 
#include <stdio.h>

void main(void)


{	int paycode = 0, hours;
	float hourly_rate, weekly_pay, weekly_salary, weekly_sales;
	
	
		printf("Enter employee paycode (-1 to end): ");
		scanf("%i", &paycode);	
	
	switch (paycode)
	while (paycode != -1)
	{
		case 1:		
			printf("	Enter the weekly salary: ");
			scanf("%f", &weekly_salary);
			weekly_salary = 400;
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_salary);	
			break;
		case 2:
			printf("	Enter the employee's hourly rate: ");
			scanf("%f", &hourly_rate);
			printf("	Enter the hours worked: ");
			scanf("%i", &hours);
			if (hours <= 40)			
			{	weekly_pay = hourly_rate * hours;
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);	
			}	
			else if (hours > 40)				
			{	weekly_pay = (hourly_rate * 40) + ((1.5 * 12.50) * 5);
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);
			}
			break;
		case 3:
			printf("	Enter the gross weekly sales: ");
			scanf("%i", &weekly_sales);
			weekly_sales = 250 + (1000 * .057);
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_sales);
			break;
	}
		
		printf("Enter employee paycode (-1 to end): ");
		scanf("%i", &paycode);	
			
		
}

[Sebastiani]

#include <stdio.h>

int main(void)
{
 int paycode = 0, hours;
 float hourly_rate, weekly_pay, weekly_salary, weekly_sales;

	 while (paycode != -1)
	{
     printf("Enter employee paycode (-1 to end): ");
	 scanf("%i", &paycode);

        switch (paycode)
	   {
	    case 1:
			printf("	Enter the weekly salary: ");
			scanf("%f", &weekly_salary);
			weekly_salary = 400;
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_salary);
			break;
		case 2:
			printf("	Enter the employee's hourly rate: ");
			scanf("%f", &hourly_rate);
			printf("	Enter the hours worked: ");
			scanf("%i", &hours);
			if (hours <= 40)
			{	weekly_pay = hourly_rate * hours;
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);
			}
			else if (hours > 40)
			{	weekly_pay = (hourly_rate * 40) + ((1.5 * 12.50) * 5);
				printf("The employee's weekly pay is $ %6.2f\n\n", weekly_pay);
			}
			break;
		case 3:
			printf("	Enter the gross weekly sales: ");
			scanf("%i", &weekly_sales);
			weekly_sales = 250 + (1000 * .057);
			printf("The employee's weekly pay is $ %6.2f\n\n", weekly_sales);
			break;

        default: paycode = -1; // assume the user wantred to bail out...

     } // end switch
	 
   } // end while

 return 0; // all important return statement
}

[curlious]

Why don't you try implementing the suggestions by Sebastiani then post the problems you are haveing with your revision.

Your switch control structure shouldn't be interrupted by the while loop. As was stated.