password

[M_amaR]

I have a simple C program which basically compares two strings and reports whether they are the same or not. Hence it can be used to verify whehter 2 given passwords are the same or not.

I wanted to know how you can make the '*' sysmbol appear instead of the password characters.

example:

if input is "admin"

Enter password : ****

Re-enter password : ****


I was doing a for loop for that, but cannot get it to work.

#include<stdio.h>
#include<conio.h>
#include<string.h>
#define ff fflush(stdin);

void main()
{
int r;
char str1[10], str2[10];
clrscr();

printf("Enter password:\n");
gets(str1);
ff;
printf("Re-enter password:\n");
gets (str2);
ff;

r=strcmp(str1, str2);

if(r==0)
{
printf("Enter");
}
else
{
printf("Exit");
}
getch();
}

i made a this small example with for loop but cannot connect it with the gets() function

#include <stdio.h>
#include <string.h>

int main() {
	char name[6] = "amar";
	int i;

	for(i = 0; i < strlen(name); i++) {
		printf("*");
	}

	printf("\n");
}

If you could help me there ..
thanks anyways.....

[Azuth]

I don't think 'getch' is portable, but you should be able to use it for this (I notive you've used it to await a key press at the end). You'd read the password one character at a time in a loop and have the loop print a '*' every time a key is pressed. Btw, your second program used int main, which is correct, void main isn't.

[Salem]

Oh boy, the poisonous trio of "void main", "fflush(stdin)" and "gets()" all in the same program!!!

Read the FAQ

[M_amaR]

ok i know this has been long... but i didn't want to continue on the code... but then i thought about it...and i got this

#include<stdio.h>
#include<conio.h>
#include<string.h>

int main()
{
int i=0, ch=0;
char str1[10];
clrscr();

printf("Enter password:\n");
for (i=0; i<80; i++)
{
ch = getch ();
if (ch == '\r' || ch == '\n') break;
if ((ch == '\b') && (i > 0))
{
printf ("\b%c\b", ' ');
i -= 2;
}
else
{
putc('*', stdout);

}
}
}

the code is a bit disoragnized ...but it now prints "*" for and input of a char

so it works...
but i cannot get it to compare the string input and the password string ??
how do i do this...

[GaPe]

#include<stdio.h>
#include<conio.h>
#include<string.h>

int main()
{
int i=0, ch=0;
char str1[10], passw[10] = {0};
clrscr();

printf("Enter password:\n");
for (i=0; i<80; i++)
{
ch = getch ();

passw[i] = ch;// now you can compare this with your string
if (ch == '\r' || ch == '\n') break;
if ((ch == '\b') && (i > 0))
{
printf ("\b%c\b", ' ');
i -= 2;
}
else
{
putc('*', stdout);

}
}
}

[M_amaR]

thx i give it a go!!!

[ronin]

the code is a bit disoragnized ...but it now prints "*" for and input of a char

so it works...
but i cannot get it to compare the string input and the password string ??
how do i do this...

Read string1, read pw str, and then try

if((strcmp(pw_str, str_input)) == 0)

[M_amaR]

thx for helping ronin,

but GaPe's post gave away the whole answer....

i finished it ..

thx for all ......