i've been trying to make this function work... but to no avail
Code:pal (int *str) { int i=0,k,flag; char x[10]; while(*(str+i)!='\0') { i++; } printf("%d", i); k=i-1; i=0; while( k>=0) { x[i]=*(str+k); printf("%c", *(str+k)); k--; i++; } flag=0; k=i; i=0; while(*(str+i)!= '\0') { if (*(str+i) != x[i]) { flag=1; break; } i++; k--; } if(flag==0) { printf("Palindrome"); } if (flag==1) { printf("Not Palindrome"); } }
Can anyone help me plz
Here's an easy way:
You could of course optimize this to use only half the length, but that's the easiest way. Of course, this doesn't count or allow for white space, and it doesn't check case sensitivity.Code:for( x = 0, y-1 = strlen( foo ); x < strlen( foo ); x++,y-- ) { if( foo[x]!=foo[y] ) printf( "Not a palindrome." ); }
Quzah.
Hope is the first step on the road to disappointment.
You have declared str as int *
This could be ok, but then you would have to cast it to char
before comparing with '\0'
like
while(((char)*(str+i))!= '\0')
easiest would be to change int *str to char *str
