Thread: PLease give a revision for pointerarrays!

Hello again!

I make a little Segfault while taking acces to to a
pointer array ... . This is my declaration:

Code:

struct data {
char *pointerarray[10][10][10];
}mystruct;
char *tmpchar;

If I read data from stdin, like this:

Code:

scanf("%s[^\n]",&tmpchar);

and try to put it into the pointerarray, like this:

Code:

strcpy(mystruct.pointerarray[0][0][0], tmpchar);

I get a Segmentation Fault! Why ?

demonus

the variable HAS to be a arraypointer because I need a 3 dimensional variable where I can put MORE THAN ONE character per address into it:

arraypointer[0][0][0]= "Hello"
arraypointer[1][1][1] = "my friends"

And they must be strings

declaring tmpchar as an array brings the same error:
Segfault !

>> arraypointer[0][0][0]= "Hello"
>> arraypointer[1][1][1] = "my friends"
>So what is in arraypointer[0][0][1] or arraypointer[0][1][0] or >arraypointer[1][0][0] ?

Do you know K.I.S.S. ? Keep It Short and Simple!

In fact the user enter ALL variables in a for(); - loop ... .
So ALL spaces will be used:

Code:

printf("Enter field 1: "); scanf("%d",aninteger);

This declares arraypointer[aninteger][0][0] !
Do you know what I mean ?

Code:

define MAX 10
struct data {
char *pointerarray[MAX][MAX];
}mystruct;
char *tmpchar, *tmpchar2;
int i,j;
main()
{
printf("Enter first field: ");
scanf("%d",i);
for(j=0;j<=MAX;j++)
{
printf("Enter second field [%d]: ",j);
scanf("%s[^\n]", &tmpchar);
// Put malloc() here; I don't know the right syntax yet...
strcpy(mystruct.pointerarray[i][j][0], tmpchar);
}
printf("ready!\n");

...
}

Do you mean this ?