The following code compiles fine. How come it core dumps when I run it?
It works when I remove the asterisk in front of the buffer variable on the 5th line. Shouldn't I always use the asterisk to reference the value the pointer points to?
Thanks,
Ed
---- code--------------------------
#include <stdio.h>
void report(char *buffer)
{
printf("Test: %s\n", *buffer);
}
int main(int argc, char *argv[])
{
char *Street = "123 Disney Way";
report(Street);
}
Don't dereference the pointer in your printf statement. printf takes pointers, so you don't need to dereference the pointer, just pass it.
[edit]
Actually, let me rephrase that. printf takes arguments depending on what scan codes you give it. Since you used %s, that means it wants a pointer. If anything ever asks for a pointer, you pass it the name of a pointer as the argument, or the address of a non-pointer.
[/edit]
Quzah.
Last edited by quzah; 07-10-2003 at 07:41 PM.
Hope is the first step on the road to disappointment.
k, then how about this. How come the first example works and the second crashes? Line 10 is the only variation between the two.
Example 1:
<code>
#include <stdio.h>
void update(char *buffer)
{
strcpy(buffer, "testing");
}
int main(int argc, char *argv)
{
char Name[20] = "Donald Duck";
update(Name);
}
</code>
Example 2:
<code>
#include <stdio.h>
void update(char *buffer)
{
strcpy(buffer, "testing");
}
int main(int argc, char *argv)
{
char *Name = "Donald Duck";
update(Name);
}
</code>
also, i think
should beCode:int main(int argc, char *argv)
Code:int main(int argc, char *argv[])
