Thread: Parameter problem

er.........
i have a function which accepts char[]

and i want to pass in a string

there's no problem with passing in :

function ("HELLO");

but i'm facing a problem when i want to pass in a string which also contains some special code character which i dunno how to represent, all i know is that i usually use this character like this :

printf ("%c", 186);

so what i want to pass into this function is something with a combination of "\tHELLO" and this '186' character

i dunno how i can achieve this as a parameter, can someone help me out?

Well you're close with what you have. Add an 's' to that printf call first.

sprintf( buffer, format, ... );

Such as:

Code:

sprintf( buf, "%s%c%c", "hello", 186, 129 );
myfun( buf );

[edit]
On a side note, 186 is greater than what a signed character uses. You're trying for extended characters, I suspect. You really should be using some other method. Perhaps using an array of unsigned characters instead.
[/edit]

Quzah.

i see, but wat do i put under buffer?

i onli see the need for the 2nd parameter, can i not create a buffer?

Originally posted by fkheng
i see, but wat do i put under buffer?

i onli see the need for the 2nd parameter, can i not create a buffer?

The common implementation here is to use an array as your buffer. However, as described, you'll have issues with your value you're trying to use, since it falls outside of the bounds of a signed character.

However, here is an example:

Code:

char buf[10] = {0};
sprintf( buf, "hello%c", '!' );
printf( "Buf contains: '%s'\n", buf );

Quzah.