Thread: Pointer question: *ptr with gets()

Hi everyone:

I wonder why when i use gets() function in statement generates an error, but when used with a pointer: *ptr it works fine:

" if (gets(input) != NULL) " -----generate an error
" if (*(ptr=gets(input) !=NULL)" -----works fine

what exactly does the pointer do here exactly??

Hopfully all those experienced programmers can answer this question....

ty.

Can you give us some more code to work with? Like a little example that does what you're talking about?

Code:

/* Little example */
#include <stdio.h>

int main(void)
{
    char line[10];

    if (gets(line) != NULL)
        puts("Woohoo! It works!");

    return 0;
}

yah..just exactly like wat u have......

Then I have no idea, it works fine for me. Try using fgets instead of gets and see how that works.

Code:

/* Little example */
#include <stdio.h>

int main(void)
{
    char line[10];

    if (fgets(line, sizeof (line), stdin) != NULL)
        puts("Woohoo! It works!");

    return 0;
}

Or if that doesn't work, you can use scanf.

Code:

/* Little example */
#include <stdio.h>

int main(void)
{
    char line[10];

    if (scanf("%9s", line) == 1)
    {
        int c;

        if ((c = getc(stdin)) != '\n' && c != EOF)
            ungetc(c, stdin);

        puts("Woohoo! It works!");
    }

    return 0;
}

Or write your own if you really need to.

Originally posted by muk_luk
Hi everyone:

I wonder why when i use gets() function in statement generates an error, but when used with a pointer: *ptr it works fine:


ty.

as i see , no one gave u the answer till now,
the answer for ur question is the following,

u should first determine the function prototype for gets
here it is

char *gets(char *s)
that means that this function reads character string and puts this string in a string s {pointer]

that is why u should use it with pointer

thank you for all ur help.....


p.s: Quzah= stubbornnnnnn!

>> *(ptr=gets(input)

Oh God! Are you sure about the language you are writing in?