My progg is calling a function from one case of a switch. Now in that function if a condition matches, I want to come out of the switch directly from the fn itself.
switch(x)
{
case 01:
-------
-------
fn();
------
--------
break;
-----
-----
}
fn()
{
------
-----
-----
if(condn)
{
exit from the switch
}
else
{
-----
}
-----
------
}
You can't exit a switch from inside a function.
The only way you're gonna be able to do that is to have the function return a value, and then check the return value of the function, and exit the switch from there.
Edit: Dang. Beaten.
Naturally I didn't feel inspired enough to read all the links for you, since I already slaved away for long hours under a blistering sun pressing the search button after typing four whole words! - Quzah
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Wont a GOTO work?
how about using a GOTO statement in the function? will it work if used cautiously?
-Harsha.
Help everyone you can
>how about using a GOTO statement in the function?
goto can't span two functions, the label and the goto have to be in the same function. You can use setjmp and longjmp, but IMHO that's a little too awkward.
Code:#include <stdio.h> #include <setjmp.h> jmp_buf jbuf; void fn() { longjmp(jbuf, -1); /* Exit switch */ } int main(void) { int c = 0; if (setjmp(jbuf) == 0) { puts("Start"); switch (c) { case 0: fn(); break; } } else puts("End"); return 0; }
