Thread: access violation!!

  1. #1

    Angry access violation!!

    void main(void) 
      char what[24];
      int base;   base = atoi(what);
      char * address = base;
        while(1) printf("%i", (char)*address++);

  2. #2
    Registered User
    Join Date
    Jul 2002
    char * address = base;
    this is pointing to the converted int, proabally some ram already used. you want to add the '&' sign to base so it points to where it is and not what it holds.

  3. #3
    C++ Developer XSquared's Avatar
    Join Date
    Jun 2002
    Ontario, Canada
    >>void main( void )


    Use int main( void ) and return 0;
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  4. #4
    ATH0 quzah's Avatar
    Join Date
    Oct 2001

    Re: access violation!!

    This code wouldn't compile.

    1) This line is wrong:

    void main(void)

    2) This is wrong:
      char what[24];
      fgets( what,24 ) );
      int base;   base = atoi(what);
    Do you even listen to your compiler? You have two ')' there when you should just have one.

    Furthermore, this is C, not C++. As such, you cannot radomly declare new variables wherever you like, unless by some odd chance, you happen to have a C99 compatible compiler.

    3) This is also wrong, as described in the first post.

    char * address = base;

    4) What are you doing?

    while(1) printf("%i", (char)*address++);

    This code will print out characters (as numbers) forever and ever and ever and ever. And why are you typcasting here? Use %c if you want characters, otherwise, lose the cast. My guess is that you're trying to do something your compiler is warning about, so you're trying to hide the warning.

    The above line is also a potential cause of access violation, because of your foolish while loop.

    Hope is the first step on the road to disappointment.

  5. #5
    Been here, done that.
    Join Date
    May 2003

    Re: access violation!!

    fgets(what,24, stdin);
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