Thread: newbie question - checking if a char array stores a number.

  1. #1
    Registered User
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    newbie question - checking if a char array stores a number.

    Hi
    Yeah, it sounds like a strange thing to do " checking if a char array stores a number", and your probably wondering why there'd be a number there anyway. Well, trust me, there is a reason.

    The thing that's confusing me, is that I assumed it would be simple enough to check if there was a specific number in a char array like so:

    Code:
    for ( i=0 ; i<stringlength ; i++){
    	if ( string[count]==1 ){
                        printf("One.\n");
     	}
    }
    What i'm actually trying to do is a little more complicated than that, but that's the problem simplified. For some reason it's just reading straight passed any 1's and continuing on without printing "one".
    I also tried casting it (string[count]) to an integer, but still had no luck.

    Please help me out.

    Thanks,
    turmoil

  2. #2
    Registered User
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    Shouldn't the array index be i not count?

  3. #3
    Registered User
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    eeer yeah . whoops. count is what i'm using in my actual code, so i got a little distracted making that example....

    so i meant:

    Code:
    for ( i=0 ; i<stringlength ; i++){
         if ( string[i]==1 ){
                        printf("One.\n");
         }
    }
    But either way, it still doesn't read any 1's in the string, when there definately are 1's there (amongst the char's).

  4. #4
    ATH0 quzah's Avatar
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    if( string[i] == '1' )

    Quzah.
    Hope is the first step on the road to disappointment.

  5. #5
    Casual Visitor
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    350
    And a more general way is to include ctype.h and then use isdigit()

    if(isdigit(myarray[index]))
    .. do something
    I haven't used a compiler in ages, so please be gentle as I try to reacclimate myself. :P

  6. #6
    Registered User
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    hey thanks heaps quzah! That's all i needed.

    (Can't use isdigit as i'm looking for specific numbers.)

    cheers,
    tumoil

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