Hi
Yeah, it sounds like a strange thing to do " checking if a char array stores a number", and your probably wondering why there'd be a number there anyway. Well, trust me, there is a reason.
The thing that's confusing me, is that I assumed it would be simple enough to check if there was a specific number in a char array like so:
What i'm actually trying to do is a little more complicated than that, but that's the problem simplified. For some reason it's just reading straight passed any 1's and continuing on without printing "one".Code:for ( i=0 ; i<stringlength ; i++){ if ( string[count]==1 ){ printf("One.\n"); } }
I also tried casting it (string[count]) to an integer, but still had no luck.
Please help me out.
Thanks,
turmoil