Thread: How to edit a string...

I have a string that has text surrounded by Quotation Marks in it:

Example: "Virginia"

How would I edit the string to keep the text in the middle but get rid of the Quotation marks?

Thanks for any help you can offer.

I ran into one problem trying it that way (and it's probably just a stupid thing on me).

What I neglected to mention is that I have an array of these strings so for example: team[1] = "Virginia"

Team is declared as team[41][40]...

What I tried was:

Code:

/* Remove the Quotes */

  for (i=1;i<number+1;i++)
  {
    *strstr(strcpy(team[i][j],team[i][j+1]), "\"") = 0;
  }

And I got two errors:
Argument of type "char" is incompatible with parameter of type "const char *".

The source of the error was team strings.

Is there something different I would have to do to get this to work in my situation?

Again thanks for your help.

here is another way to do that:-

Code:

#include<stdio.h>
#include<ctype.h>
#include<string.h>
#include<stdlib.h>

int main()
{
	char s2[]="\"Virginia\"";
	int k=0,j=0;

	puts(s2);
	printf("\n");

	k=strlen(s2);

	for(j=0;j<k;j++)
	{
		if(s2[j]!='"')printf("%c",s2[j]);
	}
	printf("\n");

	return 0;
	system("PAUSE");

}

I just saw the second way you tried it.


That one seems to have worked THANKS!

Ok... one last question if you've got a minute.

When I'm outputting my data now I'm using code that looks like:

Code:

printf("\n %-40s %-5s   %3d - %3d   %4.3f",team[mlnum[i]],abbv[mlnum[i]],mlw[mlnum[i]],mll[mlnum[i]],pct);

Everything but the abbv (%-5s) field seems to work just fine. For some reason the abbv field is producing its output and then appending some other abbv's surounded by quotes:

Example:

Code:

VIR""ABC""WES"

However this is only impacting some of the entries, others are appearing as just:

Code:

VIR

As they should...

Any idea what might cause this kind of an error?

Thanks again.

It could be that some of the strings in the abbv array are not 0 terminated, therefore the string would continue into the next array index until a 0 termination is found.

abbv[0] = VIR"
abbv[1] = "ABC"
abbv[2] = "WES"0
abbv[3] = "XXX"0

NULL termination missing from [0] and [1] but not [2] and [3].

printf("%s", abbv[0]);

would output VIR""ABC""WES"

Originally posted by Scarlet7
It could be that some of the strings in the abbv array are not 0 terminated, therefore the string would continue into the next array index until a 0 termination is found.

So if I had used your algorithm to remove the quotes from the Abbreviation, fields as well, shouldn't that have added the termination string?

I did check this in dbx and it appears that some of the strings have stuff on the end of them and aren't terminating where I expected it too...

so how would I add the 0 termination in the right spot?

Make sure that all the stings in the array are initialised to 0's before using.

char team[41][40] = {0};

If the strings are a fixed length then set the 0 at the end. i.e if all the strings are 3 then abbr[i][3] = 0

Also make sure that the array string length is big enough for the size of the string including the null at the end, add +1.

char team[41][40+1] = {0};

THANKS A TON ALL IS WORKING NOW!

(as you can tell I'm happy)