In this small program what does the 3rd line mean? Specifically on the 3rd line the [16].
Code:int main () { char s [16]; printf ("\nMeeting with an ugly boss..."); printf ("\nHow are you? (good or bad): "); scanf ("%s", &s); if (strcmp (s,"good") == 0) printf ("\nBOSS: Nope... You fired!"); else if (strcmp (s,"bad") == 0) printf ("\nBOSS: Too bad... You fired!"); else printf ("\nBOSS: Not too cooperative today?!... You fired!"); printf ("\nBOSS: Ahhh! That feels good!"); return 0; }
3rd line?
char s[16] ?
your declaring an array which can hold 16 characters
and the first character starting at position 0.
there are only 10 people in the world, those who know binary and those who dont
The [] mean that that s is a array of consecutive characters. The number iside the brackets specifies the number of characters.
s[0] is the first element of the array, s[1] is the second element array....s[15] is the last element of the array.
Arrays are commonly used in order to save a string. In your exemple, the array s will hold the string typed by the user (the scanf statement).
Ok, thanks.
And this means you're doing it wrong:
>>scanf ("%s", &s);
It should be
>>scanf ("%s", s);
as s is an array.
When you're comfortable with using scanf(), have a read of this to see how you might read input in a better manner.
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
