Thread: Slope to degrees

Does anyone know how to compute the azimuth in degrees from the given slope. If the two components (the numerator and the denominatory or x component and y component) are known. This is what I have but I am not sure that it is correct.

Code:

double ComputeAzimuth(double dbY, double dbX)
{
	int iQuadrant = 0;
	double slope;

	slope = dbY/dbX;


	if( dbX > 0 && dbY > 0)
	{
		iQuadrant = 1;
	}
	else if( dbX < 0 && dbY > 0)
	{
		iQuadrant = 2;
	}
	else if(  dbX < 0 && dbY < 0)
	{
		iQuadrant = 3;
	}
	else if(  dbX > 0 && dbY < 0)
	{
		iQuadrant = 4;
	}

	switch( iQuadrant )
	{
		case 1: return 90 - (atan(slope) * (180/PI));
		case 2: return 270 - (atan(slope) * (180/PI));
		case 3: return 270 - (atan(slope) * (180/PI));
		case 4: return 90 - (atan(slope) * (180/PI));
	}

	return 0.0;
}

By the way vertical and horizontal azimuths such as 0, 90, 180, 270 are treated as special cases so they don't need to be computed through this function.

if I understand your question properly, you wont to know how to calculate the inclination from the x axis of function.

m == slope
deg == Degree

so

inverse tan m = deg
tan deg = m

convert as need be

Hope this helps