Thread: Array Help Asap Please!!!!!!!!

I have a problem. I have a program that defines an int a[20] so that I can put 20 different values into the array. I am writing a program that will ask the user to input integers and it can be anywhere from 1 - 20 integers. I can read in the values and print them but since my loop says this:

printf("Enter random integers (max 20): "); (example) 2 3 4 2 42
int i = 0;
while (i < 19)
{
scanf("%d", a[i]);
printf("%d ", a[i]);
i++;
}

I get stuck in the never ending loop since the value may never reach nineteen. I do not know what to do because this will output the values but now I am stuck. All I need to do is just get the values from the one line of output to be written in the array at those memory locations and get out of the loop so I can finish the rest of my program.

HELp!!!

See I would do that but I have to put them in as an integer and they do not have to put all 20 integers in so my loop is becoming never ending. I would put them in as a string and cat the string but I can not do that. Please help me with my problem!!!

> you might want to try not initializing the string
> example
> str[];
> then after you get the string, by using the gets((str)string)
> the you can make the interger that you are going to use to
> start your loop a zero which means to append a null statement
> to the array as a termintor;
> ex. i=0;

Um no. This is very wrong.

char str[]; /** not valid **/

Even if it was:

fgets( str, someRandomSize, someFile );

This would kill your program because it'd be the same thing as usign an uninitalized pointer in the place of 'str'.

Quzah.

Nah, you're doing fine. You can only use unsized arrays when you are initializing them at the time of declaration:

char array[] = "My unsized array is being initialized now.";

The same goes for "tables" (arrays of structures):

Code:

struct mystruct {
   int x;
   char *name;
};

struct mystruct  myTable[] =
{
   { 1, "one" },
   { 2, "two" },
   { 3, "three" },
   { -1, "null" }
};

Quzah.

All right this is what I have right now. The only problem is go always = 1. So the loop still does not end and I am stuck at the very same place that I started at.

PLEASE HELP



#include <stdio.h>

int a[20], i, n;

int main()
{
int flag;
int go;
i=0;
printf("Enter in integers (Max 20): ");
while (i < 20)
{
a[i] = -1;
i++;
}

i = 0;
go = 1;
while(go == 1)
{
flag=a[i];
scanf("%d", &n);
a[i]=n;
printf("%d\n", a[i]);
if(flag!=a[i])
{
go=1;
i++;
}
else
{
go=0;
}

}
return 0;
}

okey, i am confused.

If i do

int elements[4];

have i got 3 or 4 elements to use. I am pretty sure i actually got 4, as in zero to three but...

Cheers
G'n'R

Yes, you have four elements if you do this:

int array[4];

However, if you are trying to use a _string_, then in essence, you only get 3 due to the NULL at the end:

char array[4] ;

Quzah.

yep, gotch ya!

and... you access element 4 with elements[3]

yep gotcha again