Thread: Exit a function

  1. #1
    Registered User
    Join Date
    Oct 2002
    Posts
    8

    Exit a function

    here's what i have...
    Code:
    void header (void)
    {
    printf("Enter the year (21st century): ");/*Asks user for the year*/
        		scanf("%d",&year);
        	if (year > 2100 || year < 2001) /*if not a valid year give error*/
    		{
    			printf ("Calendar unavailable for invalid years.\n");/*print error*/
    			exit(0);
    		}
    }
    its followed by another input function...i want to exit this function and stop the program if its not a valid year...i used exit (0); but it gives a warning .. of warning C4013: 'exit' undefined; assuming extern returning int ....i just want to exit and not continue if the condition is true...

  2. #2
    Casual Visitor
    Join Date
    Oct 2001
    Posts
    350
    include stdlib.h for exit

    I think a better option would be to return an int value. That way you can choose some sort of error routine instead of aborting. Your user most likely won't run your program too many times if he or she has to keep restarting it to enter a valid year. Just an idea.
    I haven't used a compiler in ages, so please be gentle as I try to reacclimate myself. :P

  3. #3
    Guest Sebastiani's Avatar
    Join Date
    Aug 2001
    Location
    Waterloo, Texas
    Posts
    5,708
    #include <stdlib.h>
    Code:
    #include <cmath>
    #include <complex>
    bool euler_flip(bool value)
    {
        return std::pow
        (
            std::complex<float>(std::exp(1.0)), 
            std::complex<float>(0, 1) 
            * std::complex<float>(std::atan(1.0)
            *(1 << (value + 2)))
        ).real() < 0;
    }

  4. #4
    Registered User
    Join Date
    Oct 2002
    Posts
    8
    Thanxguys...that worked...i'm such a n00b in C

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