Thread: helllllp!!!!

Well First off you might want to use another subject line like
"Im having problems using my pow function"

also code tags help. they are [ code] [ /code]


here is a quick fix that I can come up with

Code:

#include <stdio.h>
#include <math.h>

int main(void)
{
    double x = 0, y =0;
    printf("Enter x:");
    fflush(stdout);
    x = atoi(getch());
    printf("Enter y:");
    fflush(stdout);
    y = atoi(getch());
    printf("x^y = %f",pow(x,y);
    return 0;
}

You are trying to use inline functions..
I just looked over you code closer and you forgot to close your for loop..

Here is the fix to your code

Code:

#include <stdio.h>



double pow(double , double );
int main()
{
double x, y, count, power;
for (count=1; count<=15; ++count)
{
printf("enter the number you would like to use\n", x);
scanf("%lf", &x);
printf("enter the power the number is placed to\n", y);
scanf("%lf", &y);
power = pow( x , y);
printf("the answer is %5.3lf\n", power);
}
return 0;
}

double pow(double x, double y)
{
double power= x*y;
return(power);
}

:edit:
Blast Dog beat me to it while I was writing my reply.

If you want to learn C I would recomend that you get the K&R

Funny thing is that you both has printf() functions taking an argument but have no conversion specifier to take that argument.

printf("enter the number you would like to use\n", x);
printf("enter the power the number is placed to\n", y);

You dont need the x, or the y.

Sumpton I didnt even look at his printf() statements. I just fixed the for loop (you know cut and paste

I figured, and my name is stumon, lol. No biggy. Dr Dirty, something like this would pow the number.

Code:

double pow(double x, double y)
{
int i;
double x2 = x;
for (i = 0; i < y; i++){
x = x * x2;
}
return(x);
}

Or, you could include the math.h header and it has a pow() function in it. If you needed to use it.

Whadda bout this?

Code:

#include <stdio.h>

long getPow(long base, long power)
{
   if(power == 1)
      return base;
   else
      return base * getPow(base, power - 1);
}

int main()
{
  long num1, num2;
  
  printf("Enter the base: ");
  scanf("%ld", &num1);
  
  printf("Enter the power: ");
  scanf("%ld", &num2);
  
  printf("%ld^%ld = %ld", num1, num2, getPow(num1, num2));
  
  return 0;
}