printf() not displaying the value from scanf()

[Ootsonati]

Hi,

I'm a newbie to both C and programing in general, so I apologize if my question seems stupid. The problem is that whenever I try to get the user to input a number with scanf(), and output with printf(), the value comes up as 0 or 0.00. Below is a sample of what I've tried:

#include<stdio.h>

int main()
{
float example[5];
printf("please input a number.\n");
scanf(" %.02f" , example);
printf(" %.02f" , example);

system("PAUSE");
return 0;
}

I've tried compiling and execution on two different machines, with both Visual C++ and Dev C++. Can anyone tell me what I'm doing wrong? Thanks in advance,

Oot

[wml2003]

ur program have problem
it should be
scanf("%.02f",&example);

but not scanf("%.02",example);

[Vber]

Not only this, your example is an array, declare it as a simple variable, like this:

float example;

And then get the data, with the follow code:

scanf("%f",&example);

[Hammer]

Or:

float example[5];
printf("please input a number.\n");
scanf("%f" , example);
printf(" %.02f" , example[0]);

This version uses the first element of the array only.
To use a different element:

scanf("%f" , &example[1]);
printf(" %.02f" , example[1]);