1. ## structs like pointers?

is it possible to use structs like pointers? i mean with a array and pointers you could do

char temp[] = "testing";
char *spot= temp;

and then spot was temp. can you do that with structs, is it always one block of memory.

how could i take something like this, use something like spot from above and get one of the vars?

struct test {
int a;
int b;
};

2. Code:
```typedef struct
{
int a,b;
} test;
...
test t[] = {{1,2},{3,4},{4,5}};
test *p = t;
printf("%d,%d",p[1].a,p[1].b);```
Output: "3,4"

gg

3. i dont get it, you passing 3 sets of 2 when theres only 2 ints. and whats this p[1] stuff, wasnt one a value for the inits?

4. He's actually making an array of structs. Thus p[1] references the first element in the array. For referencing a single struct, here's an example.

Code:
```typedef struct
{
int a,b;
} test;
...
test t = { 1, 2 };
test *p = &t;
printf( "t.a=%d, p->a=%d", t.a, p->a );```
This would output 't.a=1, p->a=1'.

5. >Thus p[1] references the first element in the array

p[1] = the second element of the array.

6. Also if you have a pointer to an array of structures the pointer can be incremented to the next structure pointer with P++.

Code:
```#include <stdio.h>

typedef struct
{
int a,b;
} test;

test t[] = {{1,2},{3,4},{4,5}};

int main()
{
test *p = t;

for(int i = 0; i < 3; i++)
{
printf("p++ = %d,%d\n",p->a, p->b);
p++;
}

//is the same as:

p = t;
for(i = 0; i < 3; i++)
{
printf("P[i] = %d,%d\n",p[i].a, p[i].b);
}
return 0;
}```