Thread: question about open file in unix system

Hi,all
I use fopen to open a txt file in Unix , but it always fails (ipf =�@NULL ). The file 1.txt is already in the current directory.
I don' t know why. Can you give some advice?

Thanks,

--------------------------------------------------
char *File1=NULL,*File2=NULL;
FILE *ifp=NULL,*ofp=NULL;

File1= "./1.txt";
File2= "./1-1.txt";

ifp=fopen(File1,"r");
ofp=fopen(File2,"w");

char File1[] = "./1.txt";

and the same for the other file.

this works for me on UNIX

Code:

#include <stdio.h>

int main()
{
    FILE *fp1, *fp2;
    char *filename1 = "./1.txt";
    char *filename2 = "./1-1.txt";
    
    if( (fp1 = fopen( filename1, "r" ) ) == NULL)
        printf("Unable to open file.\n");
    else printf("File %s is open for reading.\n", filename1);
    
    if( (fp2 = fopen( filename2, "w" ) ) == NULL)
        printf("Unable to open file.\n");
    else printf("File %s is open for writing.\n", filename2);
             

    return 0;
}

hope this helps

printf("Unable to open file.\n");

To print out error, try using the function perror(), is better.

Originally posted by Vber
To print out error, try using the function perror(), is better.

Thanks.

I have used it, can you tell me how to know the decsription of the error?

errno =�@0x290010

It happens when fclose ends.