Thread: least common multiplier

  1. #1
    still a n00b Jaguar's Avatar
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    least common multiplier

    I've ever writen a function returning `greatest common divisor'.
    But now I need `least common multiplier' to carry on my project.
    Please anyone suggest me its concept. In order that I can write it by myself.

    Any help would be much appreciated.
    Thanks,
    slackware 10.0; kernel 2.6.7
    gcc 3.4.0; glibc 2.3.2; vim editor
    migrating to freebsd 5.4

  2. #2
    End Of Line Hammer's Avatar
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    Are you having problems with the maths or the code?
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  3. #3
    still a n00b Jaguar's Avatar
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    I have problem with math.
    I only need its concept.
    I want to write it by myself.
    Sorry in late reply.

    Thanks,
    slackware 10.0; kernel 2.6.7
    gcc 3.4.0; glibc 2.3.2; vim editor
    migrating to freebsd 5.4

  4. #4
    Just Lurking Dave_Sinkula's Avatar
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    Last edited by Dave_Sinkula; 03-14-2003 at 11:25 AM.
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

  5. #5
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    To work out by brute force:

    Start looping at the lowest of the two given numbers multiplied by two. Loop every number up to the product of the two numbers.
    In the loop, if you modulus the current tested number by the first number and the second number, and both are 0, return the current tested number.
    After the loop return the product of the two numbers.
    - Tigs

  6. #6
    Confused Magos's Avatar
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    Split the number into prime numbers. Then, for each prime number, pick the one with the most amount and multiply that to the answer.
    If that sounded too weird (I guess it did) then look at this:

    1500 = 2 * 2 * 3 * 5 * 5 * 5
    126 = 2 * 3 * 3 * 7

    For 2:s, the first one have 2 and the second has 1. 2 > 1 so we pick 2.

    For 3:s, the first one has 1 and the second has 2. 1 < 2 so we pick 2.

    For 5:s, the first one has 3 and the second one has 0. 3 > 0 so we pick 3.

    For 7:s, the first one has 0 and the second one has 1. 0 < 1 so we pick 1.

    The least common multiplier is:
    2^2 * 3^2 * 5^3 * 7^1 = 31500

    test:
    31500 = 1500 * 21
    31500 = 126 * 250

    21 = 7 * 3
    neither 7 nor 3 splits 250

    31500 is the least common multiplier!
    MagosX.com

    Give a man a fish and you feed him for a day.
    Teach a man to fish and you feed him for a lifetime.

  7. #7
    still a n00b Jaguar's Avatar
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    Thanks all of you. That is what I need.
    slackware 10.0; kernel 2.6.7
    gcc 3.4.0; glibc 2.3.2; vim editor
    migrating to freebsd 5.4

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