Thread: problem with continue

Why not just do:

Code:

#include<stdio.h>
#include<ctype.h>
int main()
{
int n;
printf("Enter a number:");
scanf("%d" , &n);
if(isdigit(n))
printf("you said %d and that's sweet\n");
return 0;
}

Or, if that doesn't work:

if (isdigit(n) && !isalpha(n))
printf("you said %d and that's sweet\n");

(dunno why you'd need that)

Also, in your printf statement, you don't print the number. It should be:

printf("you said %d and that's sweet\n", n);

Both of you are wrong. You do not use any of the "is*" functions on integers. Yes, they take integers, but they expect the range to be a valid range for 'char'. They translate that decimal value into the ascii value of the corresponding character, and tell you if that is a character. They are meant to be used like so:

Code:

char  c = '1';

if( isalpha( c ) )
    printf("%c is an alpha-numeric character.\n", c );

You do not pass it a value like 200 and
expect it to say that 200 is a number.

Code:

if( scanf("%d", &n ) == 1 )
    printf("%d is a number.\n", n );
else
    printf("You entered an invalid value.\n");

Quzah.