could somebody explain the code below in simple english?errr how what happens and when? i tried drawing diagrams but i just confused myself even more. my logic is failing me big time.
thanx a lot
Code:void rev( char * str ) { char temp, *end; end = str + strlen( str ) -1; while ( str < end ) { temp = *s; *str++ = *end; *end-- = temp; } }
oops..there was a minor error in the previous code. here it is again!
[code]
void rev( char * str ) {
char temp, *end;
end = str + strlen( str ) -1;
while ( str < end ) {
temp = *str;
*s++ = *end;
*end-- = temp;
}
}
[code]
oh no...i did it again! sorry!
Code:void rev( char * str ) { char temp, *end; end = str + strlen( str ) -1; while ( str < end ) { temp = *str; *str++ = *end; *end-- = temp; } }
Comments added by me:
Enjoy.Code:/* take a string 'str', return nothing */ void rev( char * str ) { /* Declare 1 character variable, 'tem', and a pointer to a character 'end'. */ char temp, *end; /* Point to the last character in the string. Pointer mathmatics. Add N-1 to the start of the pointer and you're at the end, where N is the length of the string. */ end = str + strlen( str ) -1; /* while the pointer 'str' is less than the pointer 'end', do the following */ while ( str < end ) { /* swap what is currently at each current pointer 'str' and 'end' and move each pointer closer to the other */ temp = *str; *str++ = *end; *end-- = temp; } }
Quzah.
Hope is the first step on the road to disappointment.
do u mean less in value? please explain. thank you so much.
/*while the pointer 'str' is less than
the pointer 'end', do the following
*/
while ( str < end )
What value? it's a pointer, it holds an memory adress, while the adress of str is smaller than end adress, do the follow.
ok i get it now! thanx!
