1. ## just trying something

a program should accept one 5 digit number eg 42139, seperate the number into individual digits seperated from one another by three spaces eg. 4 2 1 3 9

2. ## hmmm

The Full num: 42139
The first num: (42139 / 10000)
The second num: (42139 % 10000) / 1000
The third num: (42139 % 1000) / 100
The fourth num: (42139 % 100) / 10
The fifth num: (42139 % 10)

Now this just tell's you how to separate the numbers, after you know this, it's not difficul to do what you want.

3. You can do it the hard way
Code:
```#include <stdio.h>

int five_digs(int num)
{
int cnt = 0;

while (num != 0)
{
cnt++;
num /= 10;
}

return cnt == 5;
}

void print_dig(int num)
{
if (num / 10 != 0)
{
print_dig(num / 10);
}

printf("%d ", num % 10);
fflush(stdout);
}

int main(void)
{
int num;

printf("Enter a 5 digit number: ");
fflush(stdout);

if (scanf("%d", &num) != 1)
{
return 1;
}

if (five_digs(num))
{
print_dig(num);
printf("\n");
}

return 0;
}```
Or the easy way
Code:
```#include <stdio.h>
#include <string.h>

int main(void)
{
int num, len;
char snum[10];

printf("Enter a 5 digit number: ");
fflush(stdout);

if (scanf("%d", &num) != 1)
{
return 1;
}

sprintf(snum, "%d", num);

if ((len = strlen(snum)) == 5)
{
int i;

for (i = 0; i < len; i++)
{
printf("%c ", snum[i]);
fflush(stdout);
}

printf("\n");
}

return 0;
}```

4. We just got done doing this for my C++ class I am taking.

Code:
```#include<stdio.h>
#include<stdio.h>

int main()
{
int num, tenThou, thou, hund, ten,one;
printf("Enter a 5 digit number: ");
scanf("%d",&num);
tenThou=num/10000;
thou=(num%10000)/1000;
hund=(num%1000)/100;
ten=(num%100)/10;
one=num%10;
printf("%d %d %d %d %d\n",tenThou,thou,hund,ten,one);
return 0;
}```
Not the most effiecient but the easiest and fastest (coding time) way to do it.

5. Now I see where you got that programming challange idea from. LOL.

6. ## Re: just trying something

Originally posted by verlim

a program should accept one 5 digit number eg 42139, seperate the number into individual digits seperated from one another by three spaces eg. 4 2 1 3 9
You're all doing this the hard way.

Code:
```int main( void )
{
char buf[6];

printf("Enter a 5 digit number: ");
fgets( buf, 6, stdin );

printf("%c   %c   %c   %c   %c\n",
buf[0],buf[1],buf[2],buf[3],buf[4] );
return 0;
}```
That technicly does exactly what your requirements are. Furthermore, you could just apply a simple bit of math (-'0') and stick them into individual integers.

Quzah.

7. Yea well we had just done this challenge in my Advanced Placement Computer Science class and most of the kids in my class had problems with it so I thought that it might be worth posting at HDC.