Thread: just trying something

The Full num: 42139
The first num: (42139 / 10000)
The second num: (42139 % 10000) / 1000
The third num: (42139 % 1000) / 100
The fourth num: (42139 % 100) / 10
The fifth num: (42139 % 10)

Now this just tell's you how to separate the numbers, after you know this, it's not difficul to do what you want.

You can do it the hard way

Code:

#include <stdio.h>

int five_digs(int num)
{
  int cnt = 0;

  while (num != 0)
  {
    cnt++;
    num /= 10;
  }

  return cnt == 5;
}

void print_dig(int num)
{
  if (num / 10 != 0)
  {
    print_dig(num / 10);
  }

  printf("%d ", num % 10);
  fflush(stdout);
}

int main(void)
{
  int num;

  printf("Enter a 5 digit number: ");
  fflush(stdout);

  if (scanf("%d", &num) != 1)
  {
    return 1;
  }

  if (five_digs(num))
  {
    print_dig(num);
    printf("\n");
  }

  return 0;
}

Or the easy way

Code:

#include <stdio.h>
#include <string.h>

int main(void)
{
  int num, len;
  char snum[10];

  printf("Enter a 5 digit number: ");
  fflush(stdout);

  if (scanf("%d", &num) != 1)
  {
    return 1;
  }

  sprintf(snum, "%d", num);

  if ((len = strlen(snum)) == 5)
  {
    int i;

    for (i = 0; i < len; i++)
    {
      printf("%c ", snum[i]);
      fflush(stdout);
    }

    printf("\n");
  }

  return 0;
}

Originally posted by verlim

a program should accept one 5 digit number eg 42139, seperate the number into individual digits seperated from one another by three spaces eg. 4 2 1 3 9

You're all doing this the hard way.

Code:

int main( void )
{
    char buf[6];

    printf("Enter a 5 digit number: ");
    fgets( buf, 6, stdin );

    printf("%c   %c   %c   %c   %c\n",
        buf[0],buf[1],buf[2],buf[3],buf[4] );
    return 0;
}

That technicly does exactly what your requirements are. Furthermore, you could just apply a simple bit of math (-'0') and stick them into individual integers.

Quzah.