variable types

**chavezbri** · 01-16-2003

I want to put an int in to a char, but don´t know how?

**dizolve** · 01-16-2003

If you mean that you want a string of a number, as in a string like "12345" then do as so:

Code:

  #include <stdlib.h>

  char buffer[34];
  int i = 12345;

  itoa(i, buffer, 10);

The third argument will be the base; 10 = decimal, 2 = binary, 16 = hex, etc. Hope this helps.

**Vber** · 01-16-2003

and if you want just to receive an simple output (int) and assign him in a char variable, you can do this, in this way:

char num;
scanf("%d",&num);

All will be fine, but, if the input will be bigger than 255, you'll need to use int instead char.

**Cela** · 01-16-2003

>>If you mean that you want a string of a number, as in a string like "12345" then do as so:
But only if you have itoa which is not a standard function and not every compiler will support it. Or you could use sprintf, which is standard and more powerful.

Code:

#include <stdio.h>

int main(void)
{
  int num = 12345;
  char snum[6];

  sprintf(snum, "%d", num);
  printf("%s\n", snum);

  return 0;
}

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