structure pointer?

[threahdead]

heyho
my compiler gives me a warning but i dont know why:

#include<stdio.h>

void print(struct msg *ptr);

int main()
{
	struct msg
	{
		int num;
	} in;
	int *num;
	num = &in.num;
	printf("enter some number: ");
	scanf("%d", &num);
	print(num); //compiler warning: suspicious pointer conversion
	return 0;
}
void print(struct msg *ptr)
{
	printf("the value is %d", ptr);
}

the code works but the warning is making me think.
do you know why the compiler warns me?

thanks

[SMurf]

You've defined num as an "int *", and your print function takes a "struct msg *" as input. Try defining print as having "int *ptr" for input instead of "struct msg *ptr".

If want the actual value (Not its position in memory) of ptr to be printed, you need to change "ptr" in your printf statement to "*ptr" (dereferencing the pointer).

[threahdead]

it works now.
thank you!