Thread: begginer: having trouble with "if" command.

  1. #1
    Registered User
    Join Date
    Dec 2002

    Unhappy begginer: having trouble with "if" command.

    Im 15 years old and just starting out with programming. I was wondering if anyone could help a begginer out with a simple code. Basicly im adding 2 integers together, 1 is already set and the other i get from the user. If the 2 integers are equal i want a certain message to dislplay, but for some reason when i use "if" it just displays the message regardless of the value. It also will not add. Here is the code.


    #include <stdio.h>
    #include <stdlib.h>

    int one(int a, int b,int ans);
    int a;
    int b;
    int ans;
    char cnuma[20];

    int main(int argc, char *argv[])
    printf("Hello, my age is %i years old, what is your age?\n", b);


    int one(int a, int b, int ans)
    printf("You say your age is %i? Hey we are the same age!!!\n",a);
    printf("This gives us the combined age of %i\n", a);
    return 0;
    printf("You say your age is %i, this makes are combined ages %i.\n", a, ans);
    return 0;



    when i compile and run the program without the message it will state the age of the person and the combined ages like its sopposed to. when i compile it with the "if" in there it says the "if" message no matter what and instead of adding the 2 numbers it just repeats the second. Thanks for the help.

  2. #2
    Code Goddess Prelude's Avatar
    Join Date
    Sep 2001
    > if(b=a)
    Is b equal to a? It is now, you used the assignment operator (=) instead of the equality operator (==).

    My best code is written with the delete key.

  3. #3
    Registered User
    Join Date
    Dec 2002
    i c, thanks.

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