Thread: Passing Pointer-to-struct to a function!!

Hi everyone,

Ah, great... I'm having a problem before I can even post the 'real' one... I'm using telnet, with W2k, and I can't copy my codes!!
I was under W98 before, and there was a toolbar that enabled me to copy whatever was highlighted... the toolbar's gone!!
Any idea??

Ok, now let's get into the actual problem.
I have to use pointer-to-struct array (yes, that's for an assignement), and an input file.
I declared my pointers:

Code:

EMP *emp;

initialized them to NULL

Code:

for ( ;emp*; emp++)
  *emp = NULL;

but now I'm confused as to how do I pass them to other function by value, and by reference???
Do I have to declare pointers-to-pointers and pass those when I want to pass by value? and pass the pointer-to-struct when I want to pass by reference?

Those pointers are really getting to me cause I'm just getting more confused every time I have to use them!!!

emp* is also a syntax error, that should be *emp I guess.

Yes, I did write it like that (*emp that is!!)... I didn't double check what I wrote, but I'm just still trying to figure out how to copy from telnet...

Aren't

Code:

int  i;
EMP *emp[MAXPOINTERS];
for( i = 0; i < MAXPOINTERS; i++ ) {
  emp[i] = NULL;
}

and

Code:

for ( ;emp*; emp++)
  *emp = NULL;

the same thing? Obivously not... but why is that?
.... I think I got it: emp is an array, (that code was initially used for a string)... that's why it shouldn't work

Sure, but be sure to allocate (and eventually free) the array first:


int i;
EMP *emp[MAXPOINTERS];
for( i = 0; i < MAXPOINTERS; i++ ) {
emp[i] = malloc(sizeof(EMP));
}

No, but you can do:

Emp * array = malloc(sizeof(EMP)*amount);

for(i = 0; i < amount; i++){
array[i].id = i+1;
}
Which makes it easier to free, too, that is, without a loop:

delete(array);
array = NULL;