Thread: pointers and functions, with scanf, please help me

Code:

/*
	Terrance Lynch
	November 2, 2002
	Pointers to functions test
*/

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void test(int *int_pointer, int *t, int *z);
void times(int *int_pointer, int *t, int *z);
void RequestTwoIntegers(int *int_pointer, int *t, int *z);

int main()
{
	int i = 50, *p = &i;
	int x;
	int y;

	int *t = &x;
	int *z = &y;


	printf("i before the call to test = %i\n", i);
	
	RequestTwoIntegers(p, t, z);
	times(p, t, z);
	test(p, t, z);
	

}

void test(int *int_pointer, int *t, int *z)
{
	
	
	printf("i after the call to test = %i\n", *int_pointer);
}

void times(int *int_pointer, int *t, int *z)
{
	*int_pointer = *t * *z;
}

void RequestTwoIntegers(int *int_pointer, int *t, int *z)
{

	// request two integers from the user
	printf("Please enter two integers: \n");
	scanf("%i", &t);
	scanf("%i", &z);


}

I'm having trouble getting t and z from the user, the bottom function RequestTwoIntegers.

How do I set it up to accept user input, should I use scanf???

Code:

void RequestTwoIntegers(int *int_pointer, int *t, int *z)
{

	// request two integers from the user
	printf("Please enter two integers: \n");
	scanf("%i", t);     //Don't include the '&'
	scanf("%i", z);


}

t is a local pointer in the function RequestTwoIntegers(), so you shouldn't pass the address of the pointer.

cool, thanks.