Thread: doubts on scanf

  1. #1
    Registered User
    Join Date
    Sep 2002

    doubts on scanf

    My doubts ....

     int main(void)
        int i;
        scanf("%d", &i,&i);
    Why doesn't the scanf stmt show any error?

         int main(void)
         int i;
         scanf("  ",&i);
    This too doesn't show any errors.on the contrary the scanf stmt asks for input even though it does not retain the value keyed in. Why?

  2. #2
    End Of Line Hammer's Avatar
    Join Date
    Apr 2002
    Because the compiler doesn't know any better as scanf() has to process the parameters you give it. Get it wrong, and its your fault, and the program will most likely crash and burn.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

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