Thread: how to print it to a file

One slight change:

3a. Add the following lines below step 3:

Code:

if( myfile == NULL )
{
    printf("Fatal Error. Could not open file for writing.\n");
    exit( EXIT_FAILURE );
}

Alternately, you can use 'exit(0)' instead of 'EXIT_SUCCESS' or EXIT_FAILURE.

Quzah.

ok this is how i did it.... i was using fprintf and iwas getting lots of errors.. but i did it this way and all it did was just creat the file info... check it out..

Code:

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

struct data{
      char fname[25];
      char lname[25];
      char fnumb[10];
   }ph;


int main()
 {

  FILE *info;

    printf("\nType in the first and last one of the person\n");
    printf("please add a space when typing the last name\n");
    scanf("%s %s",&ph.fname, &ph.lname);
    puts("\n\n");

    printf("Please type in the persons phone number\n\n");
    scanf("%s",&ph.fnumb);
    puts("\n");

    printf("Name: %s  %s\n",ph.fname, ph.lname);
    printf("Phone#:  %s\n\n",ph.fnumb);

    info = fopen("info","w");

    if( info == NULL )
{
    printf("Fatal Error. Could not open file for writing.\n");
    exit( EXIT_FAILURE );
}

 fclose(info);

   return 0;
 }

Just in case this is the error that i get when i add fprintf


ph.c: In function `main':
ph.c:25: warning: passing arg 1 of `fprintf' from incompatible pointer type
ph.c:25: too few arguments to function `fprintf'
ph.c:26: warning: passing arg 1 of `fprintf' from incompatible pointer type
ph.c:26: too few arguments to function `fprintf'
ph.c:30: warning: passing arg 1 of `fprintf' from incompatible pointer type
ph.c:30: too few arguments to function `fprintf'