Thread: String w/number and chars...

Store them in a char array. The address 123 isn't an integer. They're actually characters also.

For example the binary value 00000001 would be interpreted differently depending on it's data type being a character or an integer. Take a look at an ascii table for more info.

Two things:

1
scanf() uses pointers. As such, you'd better be passing it an address. If not, then your call to scanf() is incorrect. If so, then yes, that'd work.

2
%s stops on spaces. So no, it won't work they way you expect it to in your example.

Quzah.

If you haven't learned fgets() yet, just learn it now:

Code:

#include <stdio.h>

int main()
{
   char address[30];
   printf("Enter your address: ");
   fgets(address, 30, stdin);
   //scanf("%s", address);
   printf("\n%s\n", address);
   return 0;
}

Try commenting out fgets and run it with scanf. Notice any difference in output if you enter "123 Fake Street"?

Let's look at the definition of fgets():

char *fgets( char *string, int n, FILE *stream );

string: Storage location for data
n: Maximum number of characters to read
stream: Pointer to FILE structure

> what's stdin for
This function normally reads from a file but in order to read from the keyboard, we use stdin. Standard input comes from the keyboard.

>what does the 30 mean (30 elements in array?), can it be used with structures?
It specifies the maximum number of characters to read. You can use it for structures but your results won't be correct. This function is used to read in strings. But you can have a string as an attribute of your structure and read that in if that's what you meant.

> I'm assuming Yoda, that you define address as a var before hand?
Look at the code. It's defined. Hehe, somebody called me Yoda

EDIT - Don't diss Quzah. He's only trying to help. He's one of the most helpful members on this board btw.

Originally posted by diddy02
and Quzah... man stop being so harsh on me! I know I forgot the & op... I was typing in a hurry.

Trust me, if you think that was harsh, you haven't seen anything yet.

At any rate, there was nothing 'harsh' in the entire post. I simply pointed out potential problem. Since you didn't show us your structure definitions, how am I supposed to know if you're using them correctly. Consider the following:

Code:

struct mystruct 
{
    char array[80];
    char letter;
};


struct mystruct myInstance;

printf("Enter a string: ");
scanf( "%s", myInstance.array );

This is the correct usage. You do not need the & sign. Why is that? Well, because you can use the name of an array as a pointer to its first element. As such, like with your example, it is possible for you to be using the name of a member of a structure, which is not simply a pointer, without the & symbol, and have it work.

So it very well may be that you DIDN'T forget the & symbol, but in fact that it didn't need it.

Now then, if "address" were simply an integer or something, here you'd need the &. This is the reason I stated:

"scanf() uses pointers. As such, you'd better be passing it an address. If not, then your call to scanf() is incorrect."

I didn't say you were incorrect, I said that you may be incorrect.

I don't understand how people are so thin skinned. You have to act like you're walking around on egg shells...

Quzah.

She mentioned something about spaces, she did NOT however mention anything about fgets.

I was never taught fgets in school either.

Can I have three different struct vars to take the data, like 123 is assigned to streetno, and then Fake is assigned to streetname and then street, or road, or drive, or crescent is assigned to streettype?

Yes. You can use fgets and store it into one string. Then break it up yourself. Or call scanf or fgets 3 times asking for the information separately.

Or you can use other specifiers for scanf which will read until any character you specify is entered. But since she hasn't taught you those, I guess you can't use them...

Quzah.