just look at this and tell me why it won't output anything, it will compile, but won't output anything, I need to know soon, real soon
#include <stdio.h>
#define value 30
int test(int x);
int main()
{
int x=1;
while(x<=value)
{
int test(int x);
x++;
}
return 0;
}
int test(int x)
{
if((x<=10)&&(x%2==0))
{
printf("%d : EVEN",x)
}
else if(x<=10)
{
printf("%d : ODD",x)
}
}
When you call the function all you want to do is give it the name of the variable you want to pass to it, not the data type as well.
int test(x);
The way you had it you were actually declaring a new int called x when one already existed. This new variable has no value so the program will either not work or spit out garbage assuming you don't get an error.
in your code here
you are not calling the function 'test' correctlyCode:int main() { int x=1; while(x<=value) { int test(int x); /* change to test(any variable declared ) */ x++; } return 0; }
you just need to code it as:
name of function(any local variable called before call of function)
test(y); /* declare y as int variable and it'll work */
Sue B.
dazed and confused
