i said it will print out the character '7' but i was wrong i guess.Code:int n; n=7; printf("%c\n", n);
The correct answer is it will print out the character whose internal code is 7. Now when i see this is it telling me it printed out the ASCII code for 7 which is 7. Not alot of sense is being made here?
can anyone please explain briefly why the correct answer is correct, please?
cj
"Be formless, shapeless, like water... You put water into a cup, it becomes the cup, you put water into a bottle, it becomes the bottle, you put it in a teapot, it becomes the teapot... Now water can flow, or it can crash, be water my friend."
-Bruce Lee
It's printing a character whose "internal value" (as you put it) is 7. Look in the ASCII chart to find out more codes.
If you want a "real" 7, you have to use
>n = '7';
[edit]http://www.asciitable.com/
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
Notice how it is treating it as a character with "%c"? If you wanted to print a 7 you would use "%d". See, if you wanted to print the character '7', you would have ot set n = 55 which is its ascii value.printf("%c\n", n);
Check this out, it might help explain it to you.
http://www.asciitable.com/
[edit] hehe u beat me to it, Hammer [/edit]
