Thread: yeah alil help for my switch problem

Hammer the book that i am using dint introduce us to pointer and arrays at the movement that is the next chapter after function so i cant use arrays and pointer in this programm....

Use seperate functions for the questions.
use the switch statement to call different functions.
Think about it, you'll understand.

hammer man help me out yo.....

/* this compiles on gcc, sorry about the sloppy paste. It seems to work correctly, as well

--conrad
*/
#include <stdio.h>
#include <time.h>
#include <stdlib.h>


int riwo ( int ,int, int, int ); //function prototype .
void rightwords ( void ); //function for the right words.
void wrongwords (void ); //function for hte wrong words.
int num1, num2, awn,type;
int diff;

int probswitch(int x)
{

switch(x) {
case 1:
printf ("How much is %d plus %d?", num1, num2 );
scanf ("%d", &awn );
break;

case 2:
printf ("How much is %d minus %d?", num1, num2 );
scanf ("%d",&awn );
break;
case 3:
printf ("How much is %d times %d?", num1, num2 );
scanf ("%d", &awn );
break;
case 4:
printf ("How much is %d divided by %d?", num1, num2 );
scanf ("%d", &awn );
break;
case 5:
type = 1+rand() % 4;
probswitch(type);
break;
}
return 0;
}
int main()
{



srand(time(NULL));

printf ("Enter the level of difficulty.1 for one-digit integers, and 2 for\ntwo-digit integers: ");
scanf ("%d", &diff );
if ( diff == 1 ){
num1 = 1+ rand () % 9;
num2 = 1+ rand() % 9; }
else {
num1 = 10+rand() %99;
num2 = 10+rand() %99;}
printf ("\nEnter the type of arithmetic problem you would like to use: \n"
"1)<---Addition\n"
"2)<---Subtraction\n"
"3)<---Multiplication\n"
"4)<---Division\n"
"5)<---random ( Addition, Subtraction, Multiplication and Division\n"
"\nPlease choose from thefollowing: ");
scanf ("%d", &type );

for (;{


switch ( type){
case 1:

case 2:

case 3:

case 4:

case 5:
probswitch(type);



}

if ( riwo (num1, num2, awn,type ) == 1) {
rightwords();
if ( diff == 1){
num1 = 1+ rand() %9;
num2 = 1+ rand() %9; }
else{
num1 = 10+rand() % 99;
num2 = 10+rand() % 99;

}}
else
wrongwords();
}



system ("PAUSE");
return 0;
}
int riwo (int a, int b, int tot, int ty )
{

if ( ty == 1 ){
if ( tot == a+b )
return (1);
else
return (0); }
if ( ty == 2) {
if ( tot == a-b )
return (1);
else
return (0); }
if (ty == 3 ) {
if ( tot == a*b )
return (1);
else
return (0);}
if ( ty == 4 ) {
if ( tot == b/a )
return (1);
else
return (0); }

}

void rightwords( void )

{
int right;

right = 1+rand () % 4;

switch ( right ){

case 1:
printf ("Very good!\n");
break;

case 2:
printf ("Excellent!\n");
break;

case 3:
printf ("Nice work!\n");
break;

case 4:
printf ("Keep up the good work!\n");
break;
}

}

void wrongwords ( void )
{
int wrong;
wrong = 1+rand() % 4;

switch ( wrong ){

case 1:
printf ("No. Please try again.\n");
break;

case 2:
printf ("Wrong. Try once more.\n");
break;

case 3:
printf ("Don't give up!\n");
break;

case 4:
printf ("No.keep trying\n");
break;
}

}