Thread: Having some problem with my simple calculator

I am just a newbie in programming.

Code
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#include <stdio.h>

char result(char);

void main()
{

char opr, a = 'Y';
float num[100], ans, total=0;

do{

int counter=0;

do{

scanf("%f", &num[counter]);

if(counter>0)
{

if (opr == '+')
ans += num[counter];

if(opr == '-')
ans -= num[counter];

if (opr == '*')
ans *= num[counter];

if (opr == '/')
ans /= num[counter];

}

else
{
ans = num[counter];
}


total=ans;

opr=getchar();
opr=getchar();

if (opr == '=')
printf("Total is %.2f", total);

counter++;

}while (opr != '=');


}while (result(a) == 'Y');
}



char result (char x)
{

char answer;

printf("\nDo you wish to continue?\n(Y/N)\n");

scanf("%c", &answer);
scanf("%c", &answer);

return answer;

}

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How do I compare the operators inserted by the user. We know that the * operator comes before + or - operator. For example,

1+2*3=7

but my simple calculator only performs

1+2*3=9

how do I code it in a way that it follows the rules of operators precedence.

(*This is an assignment)

we just did a calculator contest. there's some source code in the general board.

I know a lot of teachers will teach the use of
void main( ) and never introduce the students
to int main( void ). What a shame. I think they
believe it's for simplicity, but it's plain wrong.
Go with...

Code:

int main( void )
//code here
return 0;

-fox