Thread: Some homework help?

My desired output is the following

Code:

__*
_***
*****

The underscores represent space. This is what I've done so far... please help because I'm really confused.

Code:

#include <stdio.h>
#include <conio.h>

void main()

{

	int value1, space, star;	
	printf("\n\n");	
	for(value1=5; value1>=1; value1=value1-2)	

		

	   {

		


	   	for(space=1; space==value1/2; space++)	
		
		

	   	   {
	
			printf(" ");	
		   
	   	   }

			
		
		

		   for(star=0; star < 6-value1; star++)		

		      {

			printf("*");	
			
		      }
			
	printf("\n");


	   }
		
	printf("%d  %d  %d", value1, space, star);

   getch();	

}

With the above this is my output::

*
_***_
*****

Except for the first star it's all good. And can someone please quickly explain how for loops execute all of their statements/conditions if another for loop is enveloped? I'm really confused and can't concentrate on anything... I'm just typing something, compiling and doing it over and over. For example... I have no idea why I put "star < 6-value1;" in the third for loop. I know that it means that star is less than 6 subtracted by value 1... but if value1 starts out as 5 then should star always be a negative? Please help!! TIA.

Here's one way of doing it.

Declare a 2X2 int array:

Code:

int array[5][5];
int i,j;
//Initialize all the value to zero
for(i=0;i<5;i++)
    for(j=0;j<5;j++)
         array[i][j] = 0;

Now you can assign '*' to the elements that you want.

Thank you for your timely reply but I can't use Array and stuff-I haven't learned it yet. Sorry. Is there any other way I can do it using what I did?

ANd for the FOR loop, I know how it works... I just get confused when there's enveloped for loops, one for loop in another... anyone mind explaining how those execute too? I read all the tuts on this site to no avail.

Uh, that's great, but I don't understand ... .. any of it.

Sorry to keep bothering all of you... is there anyway I can modify my current code to do it?

So If I had something like:

Code:

for(blah; blah; blah)
  {
     for(blah; blah; blah)
      {

           for(blah; blah; blah)
           {
           }

       }

   }

It executes the first for, and if the condition is TRUE, then it executes the modification of the var. So if it's a-- and a is = to 5, then a becomes 4? Then it goes to the second for loop, checks blah, blah is TRUE, so it mods blah then it goes to third loop, checks blah, blah is TRUE, so it executes whatever is in body , then what? back to outer? Outermost? TIA...

And what of my homework!?

Here's a working version of you wanted to do:

Code:

#include <stdio.h>

#define MAX 10

int main()
{
	int value1, space;	
	int i = 0;
	printf("\n\n");	
	for(value1 = MAX; value1 >= 1; value1 -= 2)	
	{
		space = 0;
		i = value1 - 1;
		while(space != value1/2)
		{
			printf(" ");
			space++;
		}
		while(i < MAX)
	    {
			printf("*");
			i++;
		}
		printf("\n");
	}
	printf("%d  %d", value1, space);
	
	return 0;
}

I kind of get it... but I'm still really confused!! And ........ed! ........ed to the mAx! Does a for loop in a for loop run until its condition is false or just run it's body once and then go back and give control back to the outer for loop!?

A nested for loop runs it's entire length then goes back to the original. If the original condition is still met, it runs the entire nested loop again.

for example

Code:

int i,j;

for( i=0; i<3; i++)
{
     for( j=0; j<5; j++ )
        printf("%d", j);
     printf("\n");
}

would produce:

01234
01234
01234

Code:

for( i = 0; i < 3; i++)
{
      //do what's in here

      for( j = 0; j < 10; j++)
      {
              //do what's in here
      }
}

Let's analyze :

First, i is set to zero in the main/outer loop.
1. Then the program jumps into the loop and sees another for
loop.

2. Now the inner loop must be completed before the program
can jump out of it.

3. j is set to zero and program loops until j equals 10.

4. Now it jump's out of inner loop and sees the end of the
main/outer loop, so it increments i.

5. Now go back to step 1. if i is not equal 3.

It's beginning to sink in! (Thanks!!!!!!) Now, if I have something like this:

Code:

for(x=5; x>=1; x--)

   {
        for(y=1; y<=x; y++)

       {

          printf("printmenow")

       }

   }

So now will printmenow loop itself until y=x? And for the first for, does x-- happen right away? Meaning, will the second loop regard x's value as 4? TIA!

Yes, print me now will loop until y=x, then it will start all over again with x=4. That probably answers your second question, the block of code is executed, then the increment/decrement takes place.