Thread: bit shifting

  1. #1

    bit shifting

    I am at a total loss as to why this doesn't work

    int temp[2];
    int shift;

    shift = temp[0]
    shift = shift<<3>>3;

    I am trying to 0 the upper bytes to extract the value stored in bits 0-4. The result value is higher than 32. How can this be?

  2. #2
    Join Date
    Aug 2001
    Groningen (NL)
    >shift = shift<<3>>3;

    Here you shift the bits first 3 bits to left and then back to 3. Assuming an int is 4 bytes, 32 bits, probably on ly the last 3 bits will be set to zero.

    If you want to get the value of the first 3 bits and want to use bit-operators, there are other ways, then you could do something like this.

    111 (bin) = 7 (dec)

    So you could define a mask like this:

    #define FIRST_3_BITS_MASK 0x07

    And get the value like this:

    shift = shift & FIRST_3_BITS_MASK;

  3. #3
    Im back! shaik786's Avatar
    Join Date
    Jun 2002
    Bangalore, India
    >shift = shift<<3>>3;
    You are not trying to zeor the higher bits here, though might just work in a few cases. To zero the desired bits, use the & (AND) Operator.
    shift = shift & 0xf0;
    will give you the higher 4 bits of the variable shift.

  4. #4
    Banned borko_b's Avatar
    Join Date
    Jun 2002
    Well... I live in Bulgaria :)
    Which bits exactly do you want??
    I can't visualize them like that

    post them like this:

    <- Highbits Lowbits->
    00001111 00000000 00000000 00000000

  5. #5
    Registered User
    Join Date
    Jul 2002
    shift/fill warning.

    The shift operators << and >> perform left and right shifts of their left
    operand by the number of bit positions given by the left operand.
    Thus x << 2 shifts the value of x left by two positions and x >> 2 shifts
    the value right by two positions.

    Left shifting always fills vacated bits with zero.

    Right shifting an unsigned quantity always fills vacated bits with zero.
    Right shifting a signed quantity will fill the sign bits ("arithmatic shift")
    on some machines and with 0 bits ("logical shift") on others.

    if x = 4

     x = x << 2;
     x <<= 2;
    both cases yield a binary 16

    Definition taken out of K&R second edition page 49.
    Last edited by jerryvtts; 07-15-2002 at 12:09 AM.

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