Thread: I need help counting letters., folk!

Hello,
I am writing a program using getchar() that reads characters from the keyboard until the # sentinnel character in encountered. The program should count the number of occurrences of the letters a, b, and c.

I am goig pretty good here but ran smack into the damn wall with the last sentence. where can i get help from here. How do i get it to count the number of letters a,b, and c?
TOTALLY BODACIOUS!

#include<stdio.h>
#include<ctype.h>

int found_next_word(void);

int main(void)
{
int word_count=0;
while (found_next_word() == 1)
++word_count;
printf("Number of words = %d\n\n", word_count);
int found_next_word();
return 0;
}

int found_next_word(void)
{
int c;

while (isspace(c = getchar()))
;
if (c == '#')
printf("You can not use this # symbol. Please try again.\n");
while (c == '#')
return 0;
if (c != EOF) {
while ((c = getchar()) != EOF && !isspace(c))
;
return 1;
}
return 0;
}

int a[256]={0},b;
FILE*c=fopen("somefile","r");
while((b=fgetc(c))!=EOF)letters[a]++;
fclose(c);

Nice and compact.

Quzah.

Originally posted by quzah
int a[256]={0},b;
FILE*c=fopen("somefile","r");
while((b=fgetc(c))!=EOF)letters[a]++;
fclose(c);

Nice and compact.

Maybe compact, but not quite correct You've confused letters, b and a. Here's a working version:

Code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
	int a[256]={0},b;
	FILE *fp;
	
	if ((fp = fopen("test.txt","r")) == NULL)
	{
		perror("open failed");
		return (EXIT_FAILURE);
	}
	
	while((b=fgetc(fp))!=EOF)
		a[b]++;
	
	fclose(fp);
	
	for (b = 0; b < 256; b++)
		printf ("0x%02x %d\n", b, a[b]);

	return (EXIT_SUCCESS);
}

getchar() reads a character from the standard input, usually the
keyboard. getchar will also 'echo" the typed character to the standard output, usually the user screen.


I couldn't tell exactly how you wanted this program to work but here's an example.

Code:

#include <stdio.h>

int main(void)
{
  int char_count = 0;
  char next_char = '\0';

  printf(" Enter characters but not the # sign <>");
  for(;;)
  {
    next_char = getchar();
    switch(next_char)
   {
    case 'a': case 'b': case 'c':
    char_count++;
    printf(" a,b,c count = %d\n", char_count);
    break;

    default: break;
   } // end switch(next_char)

   if(next_char == '#')
   {
    puts(" I said not to enter the # sign!");
    break;
  } // end if(next_char == '#')
 } // end for(;;)
} // end int main(void)

Originally posted by Hammer
[B]
Maybe compact, but not quite correct You've confused letters, b and a. Here's a working version:

Code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
	int a[256]={0},b;
	FILE *fp;
	
	if ((fp = fopen("test.txt","r")) == NULL)
	{
		perror("open failed");
		return (EXIT_FAILURE);
	}
	
	while((b=fgetc(fp))!=EOF)
		a[b]++;
	
	fclose(fp);
	
	for (b = 0; b < 256; b++)
		printf ("0x%02x %d\n", b, a);

	return (EXIT_SUCCESS);
}

Correct only under the assumption that char is unsigned and UCHAR_MAX is 255, on some implementations char may be signed , so a negative value of b will cause the program to crash

He may be right. EOF is -1.