I want to generate random number between 0-1,000,000
but I can not generate random number that have much value because data type int and long do not have much value. If I want random number 0-1,000,000. How can I do that?
Thank you.
code:
.................................................. .................
long i;
srand( (unsigned)time(NULL) );
i = rand()%10000000;
.................................................. .................
Get a new compiler. Integers are (now a days) 32 bits. This produces (signed) a number between -2,000,000,000 and +2,000,000,000.Originally posted by ooosawaddee3
I want to generate random number between 0-1,000,000
but I can not generate random number that have much value because data type int and long do not have much value. If I want random number 0-1,000,000. How can I do that?
Thank you.
Try this:
Quzah.Code:#include <stdio.h> int main ( void ) { printf("I have a %d compiler!\n", sizeof( int ) == 2 ? 16 : sizeof( int ) == 4 ? 32 : sizeof( int ) == 8 ? 64 ); return 0; }
Hope is the first step on the road to disappointment.
Or, you can go about this way, but you might be missing out quite some digits. I'm basically concatenating two 2-byte integers, to form a 4 byte value, large enough to hold your limit: 0 to 10000000
Code:#include <stdio.h> #include <stdlib.h> int main(void) { long l; srand(65535U); while(1) { l = ((long)rand() % 65535L) | ((long)rand() % 65535L) << 16; l = l % 10000000L; printf(" %ld\n", l); } return(0); }
