Thread: Hi this programm is interesting and tough..

First off, post your code. We'll help from there. This is a farily easy problem.

left, center, right

center always stays the same
left increments once each loop untill it reaches the far right side
right decrements once each loop until it reaches position 0
Pesudocode.

Code:

do
{
    for( x = 0; x < width; x++ )
        if( left != right )
            if( x != left ) print a *
            else print a space
            if( x != right ) print a *
            else print a 
        if( x == center ) print a space
    left++, right++
while( left != width -1 );

I'll leave the rest to you.

Quzah.

Here's a skeleton that pretty much does half the work. I don't want to give the answer because... well, this really is something you need to understand.

Code:

#include <stdio.h>

int main (void) {
  int i, j;
  for (i = 1; i < 8; i++) 
  {
    // Maybe you'll need another for loop here for some of the problems?
    for (j = 0; j < 8; j++)  // The parameters of the for loop will have to change
    {       
      printf ("*");
    }
    printf ("\n");
  }
  return 0;
}

Using code tags on this board will help keep the layout of what you are typing.

Oh how dissapointing. I thought that was supposed to be all one pattern. Now I find out it's just something extremely simple. Sigh...

I was hoping they wanted something fun like:

Code:

#include <stdio.h>
int main ( void )
{
	int w=21,l=0,r=w-1,c=w/2,x;
	do
	{
		for( x = 0; x < w; x++ )
		{
			if( l != r )
			{
				if( x == l  || x == r || x == c )
					printf(" ");
				else
					printf("*");

			}
			else
				printf(" ");
		}
		l++;
		r--;
		printf("\n");
	}
	while( l != w-1 );
	return 0;
}

Quzah.

>I was hoping they wanted something fun
You should know better than to get your hopes up, we don't get that lucky.

-Prelude