Thread: Little help please

I am assuming that this is a very stupid question but I am learning this stuff and anyways I was just playing around trying to make a program that uses constants, it only adds like 2 numbers to the users number but anyways when I compile it I get this warning:

warning C4244: '=' : conversion from 'double' to 'int', possible loss of data

Now I don't know how to fix it though I have an idea of what the problem is, like you can't have data in one type of a variable/constant and then move it to another type but as of yet.
There is one other thing, this error only appears sometimes, I will open it, compile it will say the compiler needs to create these files(blah blah blah) then it will be fine, I then took out a "\n" to make in neater and it gave me the warning but then I executed it and it screwed up as usual but when I recompiled the warning was gone so I don't get it.

I don't know how to fix it, can someone help please?

Code:

#include <stdio.h>

/*This program is designed to test how literal constants and other types of constants work.*/

#define DECIMAL .2354698
const int whole = 10;
int userVariable;
int userTotal;

void userNumber(void)
{
	printf("This program will take whatever number you enter and add .234698 to it, and then");
	printf("add 10 to it as well, it is a test to see how constants work\n\n");
	printf("Please enter your number and the program will add to it: ");
	scanf("%i", &userVariable);
	userTotal = DECIMAL + whole + userVariable;
}

main(void)
{
	userNumber();
	printf("\nThe result of adding %f and %i to %f is: %f\n", DECIMAL, whole, userVariable, userTotal);
	
	return 0;
}

Thanks a lot

Problem:

your converting form a float point value to an int, that means
all your float specific data will be lost.

Solution:

your dealing with a floating point value.
use all doubles or floats.

I think that the programm final printf wont show what you expect it to show since userVariable, userTotal are ints and you are using the float specifier %f when you should be using the int specifier %d to show the data.

Isnt that ryt?? If am wrong somebody fix it, I'm new although I thinks that's part of the problem.

Ok, I tried to do enforce the changes that you suggested and it almost worked. The only problem is that it does display an answer. For example lets say I entered the number 2 it says that the answer is 12(so I am not just getting a 0 this time) but it doesn't add on the decimal constant, I tried to change it to a float to see what would happen and it gives me a number like -235467 or something along that line, what should I do?

P.S.

Here is the line of code that the 'warning' is on and what the warning is if you want to take a look.


Here is the main part of the problem:

Code:

void userNumber(void)
{

	printf("Please enter your number and the program will add to it: ");
	scanf("%i", &userVariable);
	userTotal = DECIMAL + whole + userVariable;
}


/*Here is the line that is messing things up:*/

userTotal = DECIMAL + whole + userVariable;

So if anyone can help I would appreciate it, I think that it is bad because I am adding numbers that don't agree with one another but I don't know that much yet so...

Thanks Salem that worked just fine