argc,argv
hi,
how can i pass arguments like main does? i mean as we declare a function say, Func(int x, int y), this function only takes 2 int arguments but main can pass in argc arguments. can we make a function like main that takes a few arguments?
please advice. thanks.
thanatos
Code:#include <stdio.h> void myfunc(int count, char *args[]) { int i; for (i = 0; i < count; i++) printf("Arg: %s\n", args[i]); } int main(void) { char *arglist[] = {"arg1", "arg2"}; int argnum = 2; myfunc(argnum, arglist); return 0; }
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
The main function doesn't pass argc arguments but only 2 (argc and argv, or whatever you want to call them).
The second argument is an array of character pointers/arrays.
If you want to pass a various number of arguments (like printf) you can use a variable argument list (va_list).
However this is not standard and differs on each OS/compiler.
va_arg and family are ANSI C.Originally posted by Monster
(va_list).
However this is not standard and differs on each OS/compiler.
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
Still learning every day.....
Thanks for the info Hammer.
thanks
thank you very much.
thanatos
