Thread: to assign a double and output it

This would be the correct code. Compare this to your code.

Code:

#include <stdio.h>

int main(void)
{
    char *dint1 = "poi";
    char *dint2 = "ghj";
    char *dint3 = "ggg";

    char *array123[3] = {dint1, dint2, dint3};

    printf("%s\n", array123[0]);

  return 0;
}

It does not surprise me that you are trying to learn C from a painfully inadequate tutorial instead of a very thorough book!

If you don't want to take the time to learn the language from the beginning rather than jumping into trying to write an array of pointers to char strings, then I cannot help you any further.

Good luck!

Originally Posted by rstanley

This would be the correct code. Compare this to your code.

Code:

#include <stdio.h>

int main(void)
{
    char *dint1 = "poi";
    char *dint2 = "ghj";
    char *dint3 = "ggg";

    char *array123[3] = {dint1, dint2, dint3};

    printf("%s\n", array123[0]);

  return 0;
}

It does not surprise me that you are trying to learn C from a painfully inadequate tutorial instead of a very thorough book!

If you don't want to take the time to learn the language from the beginning rather than jumping into trying to write an array of pointers to char strings, then I cannot help you any further.

Good luck!

Thanks,

my code was the same instead of the

Code:

*

=]

Originally Posted by WaterSerpentM

Thanks,

my code was the same instead of the

Code:

*

=]

char something; is a far cry from char *something;!!!!

Compare the printf() on my line 11 with the comparable line in your code! NOT the same!!!

Originally Posted by rstanley

char something; is a far cry from char *something;!!!!

Compare the printf() on my line 11 with the comparable line in your code! NOT the same!!!

yup, i get the code

Code:

    printf("%s\n", array123[0]);
    printf("%s\n", array123[1]);
    printf("%s\n", array123[2]);