im trying to convert a string into an array
cint1 is "1abcd" (char)
the entire code is:Code:char archar[] = {cint1}; printf("%s", archar[0]);
Code:int int1; char char1[30] = "a"; char char2[30] = "b"; char char3[30] = "c"; char char4[30] = "d"; char cint1[40] = ""; int1 = 1; itoa(int1,cint1,10); strcat(char1,char2); strcat(char1,char3); strcat(char1,char4); strcat(cint1,char1); printf("%s",cint1); char archar[] = {cint1}; printf("%s", archar[0]);
Last edited by WaterSerpentM; 10-15-2023 at 06:59 PM.
This is so wrong! You really need to study a good up to date book on the C Programming Language rather than try to hack your way trying to use a non-standard function in such a ridiculous way!
When I am near my computer later I will explain further.
ive figured it out
Code:char my_string[] = {""}; strcpy (cint2,my_string);
No, you didn't! Will respond later.Originally Posted by WaterSerpentM
ye you're right, it outputs a blank line
