Thread: current time

I tried printing out the current time on my computer through a character string, by using a pointer. The program works fine, except for one small glitch....it's not printing out the correct time. Instead it's printing out some day in January 2116. I figure it has to be somewhere in the code for the address of the current time.
Here's the code, maybe someone can show me where it went wrong.

Code:

#include <stdio.h>
#include <time.h>

void GetTimeDate (void);

int main()
{
   printf("Before the GetTimeDate() function is called.\n");
   GetDateTime();
   printf("After the GetDateTime() function is called.\n");
   return 0;
}

/**********************************The GetDateTime function**************************************/

GetDateTime (void)
{ 
   time_t now;
   int i;
   char *str;
   
   printf("Within the GetDateTime() function.\n");
   time(&now);
   str = asctime(localtime(&now));
   printf("The current date and time is ");
   for (i=0; str[i]; i++)
       printf("%c", str[i]);   
}

Nymph

I think this is because the asctime functione expects a struct tm argument and not a time_t (long).
You can use the localtime function (corrects for local time zone) to convert the time_t to a tm structure.

Code:

void GetDateTime (void)
{ 
   time_t now;
   struct tm *newtime;
   
   printf("Within the GetDateTime() function.\n");
   time(&now); /* get time as long */
   newtime = localtime(&now); /* convert to local time */
   
   printf("The current date and time is: %s\n", asctime(newtime));
}