defined behaviour

[cooper1200]

lets suppose we have the following silly function

void func()
{
     int idiff = 0, x = 7, y = 2;
     
     idiff = x/y;

im sure i read or was told that the value of idiff would be undefined. However, i seem to come across it a lot and used to get the answer 3 in this case.

second question
suppose we have have the following if statement

if ( func(p) && p > iMax )
{
      //some code.....

is that the same as

//a)                        or            b)
if ( func(p) )                          if ( p > iMax )
{                                          {
      if ( p > iMax )                       if ( func(p) )
      {                                         {

i know it seems a trivial thing but it could save func being called if p is less than iMax

[Salem]

> im sure i read or was told that the value of idiff would be undefined.
It looks fine to me.

Sure, if y is ever zero, then you're on your own at that point.

> i know it seems a trivial thing but it could save func being called if p is less than iMax
&& and || have very specific semantics.
Specifically, the left hand side is ALWAYS evaluated first.

In the case of &&, the right hand side is only evaluated if the left is true.
In the case of ||, the right hand side is only evaluated if the left is false.

So it would seem you mean to have
if ( p > iMax && func(p) )