Hey Guys,

This is a crazy problem. I'm doing some testing to make sure I understand how to use the pointers to arrays before I finish the code. If I run the code and type in 00 or 11 it works correctly or at least appears to. If you type in 10, the result is 'twenty'. It's crazy!

Code:
//http://knking.com/books/c2/answers/c13.html
#include <stdio.h>


int main(){
    char *digOne[]={"twenty", "thirty", "fourty", "fifty", "sixty", "seventy", "eighty", "ninety"};
    char *digTwo[]={"zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine"};
    char *digThree[]={"ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
    char num[2];
    printf("Enter a two-digit number: ");
    scanf("%s", num);


    if(num[0]==48&&num[1]==48){         //if 00 is entered
        printf("%s",digTwo[0]);         //prints zero
    }
    else if(num[0]==49&&num[1]==48){    //if 10 is entered
        printf("%s",digThree[0]);       //prints twenty?   CRAZY!!!
    }
    else if(num[0]==49&&num[1]==49){    //if 11 is entered
        printf("%s",digThree[1]);       //prints eleven
    }
    return 0;
}
If I comment out
Code:
//char *digOne[]={ ...
and then run the program, if I enter 10 again, it prints zero. What The Heck is wrong with what I wrote or with my head?